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Oracle Introduction to Oracle9i: SQL Sample Questions:

1. Evaluate this SQL statement:
SELECT e.emp_name, d.dept_name
FROM employees e
JOIN departments d
USING (department_id)
WHERE d.department_id NOT IN (10,40)
ORDER BY dept_name;
The statement fails when executed. Which change fixes the error?

A) prefix the column in the ORDER BY clause with the table alias
B) remove the ORDER BY clause
C) remove the table alias from the SELECT clause
D) prefix the column in the USING clause with the table alias
E) replace the condition
"d.department_id NOT IN (10,40)"
in the WHERE clause with
"d.department_id <> 10 AND d.department_id <> 40"
F) remove the table alias prefix from the WHERE clause

2. Which describes the default behavior when you create a table?

A) Tables are created in the public schema.
B) The table is accessible to all users.
C) Tables are created in your schema.
D) Tables are created in the DBA schema.
E) You must specify the schema when the table is created.

3. Examine the structure of the EMPLOYEES and NEW_EMPLOYEES tables:
EMPLOYEES
EMPLOYEE_ID NUMBER Primary Key
FIRST_NAME VARCHAR2(25)
LAST_NAME VARCHAR2(25)
HIRE_DATE DATE
NEW_EMPLOYEES
EMPLOYEE_ID NUMBER Primary Key
NAME VARCHAR2(60)
Which MERGE statement is valid?

A) MERGE INTO new_employees cUSING employees e ON (c.employee_id = e.employee_id) WHEN EXISTS THEN UPDATE SET
B) MERGE new_employees c FROM employees e ON (c.employee_id = e.employee_id) WHEN MATCHED THEN UPDATE SET
C) MERGE INTO new_employees c USING employees e ON (c.employee_id = e.employee_id) WHEN MATCHED THEN UPDATE SET
D) name = e.first_name ||','|| e.last_name WHEN NOT MATCHED THEN INSERT value S(e.employee_id, e.first_name ||', '||e.last_name);
E) MERGE new_employees c USING employees e ON (c.employee_id = e.employee_id) WHEN EXISTS THEN UPDATE SET
F) name = e.first_name ||','|| e.last_name WHEN NOT MATCHED THEN INSERT INTO new_employees valueS(e.employee_id, e.first_name ||', '||e.last_name);
G) name = e.first_name ||','|| e.last_name WHEN NOT MATCHED THEN INSERT valueS(e.employee_id, e.first_name ||', '||e.last_name);
H) name = e.first_name ||','|| e.last_name WHEN NOT MATCHED THEN INSERT value S(e.employee_id, e.first_name ||', '||e.last_name);

4. What are two reasons to create synonyms? (Choose two.)

A) You have too many tables.
B) Your tables have difficult names.
C) You have too many columns in your tables.
D) Your tables names are too long.
E) You want to use another schema's tables.
F) You want to work on your own tables.

5. The CUSTOMERS table has these columns:

The CUSTOMER_ID column is the primary key for the table.
Which two statements find the number of customers? (Choose two.)

A) SELECT TOTAL(*) FROM customers;
B) SELECT COUNT(customer_id) FROM customers;
C) SELECT COUNT(customers) FROM customers;
D) SELECT COUNT(*) FROM customers;
E) SELECT TOTAL(customer_name) FROM customers;
F) SELECT TOTAL(customer_id) FROM customers;

Solutions: